2x^2+3x+5=90

Solution for 2x^2+3x+5=90 equation:

2x^2+3x+5=90

We move all terms to the left:

2x^2+3x+5-(90)=0

We add all the numbers together, and all the variables

2x^2+3x-85=0

a = 2; b = 3; c = -85;
Δ = b2-4ac
Δ = 32-4·2·(-85)
Δ = 689
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-\sqrt{689}}{2*2}=\frac{-3-\sqrt{689}}{4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+\sqrt{689}}{2*2}=\frac{-3+\sqrt{689}}{4}
$